For the cubic P(x) = x^3 - 6x^2 + 11x - 6, what is the product of its zeros?

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Multiple Choice

For the cubic P(x) = x^3 - 6x^2 + 11x - 6, what is the product of its zeros?

Explanation:
The product of the zeros of a cubic is tied to the constant term and the leading coefficient. For a cubic a x^3 + b x^2 + c x + d, the product r1 r2 r3 equals -d divided by a. Here the leading coefficient is 1 and the constant term is -6, so the product is -(-6)/1 = 6. You can also factor the polynomial as (x-1)(x-2)(x-3), confirming the zeros are 1, 2, and 3 and their product is 6.

The product of the zeros of a cubic is tied to the constant term and the leading coefficient. For a cubic a x^3 + b x^2 + c x + d, the product r1 r2 r3 equals -d divided by a. Here the leading coefficient is 1 and the constant term is -6, so the product is -(-6)/1 = 6. You can also factor the polynomial as (x-1)(x-2)(x-3), confirming the zeros are 1, 2, and 3 and their product is 6.

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