For y = -3(x - 1)^2 + 4, what is the axis of symmetry?

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Multiple Choice

For y = -3(x - 1)^2 + 4, what is the axis of symmetry?

Explanation:
In a parabola written as y = a(x - h)^2 + k, the axis of symmetry is the vertical line x = h. Here, the equation is y = -3(x - 1)^2 + 4, so h = 1. The axis of symmetry is x = 1. The coefficient -3 only affects the direction and width of the parabola, not its axis. The vertex is at (1, 4), and the vertical line through that vertex is x = 1, which is the axis. The other lines (x = 0, x = -1, x = 4) wouldn’t pass through the vertex, so they aren’t the axis.

In a parabola written as y = a(x - h)^2 + k, the axis of symmetry is the vertical line x = h. Here, the equation is y = -3(x - 1)^2 + 4, so h = 1. The axis of symmetry is x = 1. The coefficient -3 only affects the direction and width of the parabola, not its axis. The vertex is at (1, 4), and the vertical line through that vertex is x = 1, which is the axis. The other lines (x = 0, x = -1, x = 4) wouldn’t pass through the vertex, so they aren’t the axis.

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