For y = -3(x + 4)^2 + 2, which description is correct?

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Multiple Choice

For y = -3(x + 4)^2 + 2, which description is correct?

Explanation:
In vertex form, y = a(x − h)^2 + k, the vertex is (h, k). The sign and size of a tell how the graph stretches, flips, and which way it opens: if a is negative, the parabola reflects across the x-axis and opens downward; if |a| > 1, the graph is vertically stretched (narrower) by a factor of |a|; if |a| < 1, it’s vertically shrunk (wider). For y = -3(x + 4)^2 + 2, rewrite as y = a(x − h)^2 + k with h = −4, k = 2, a = −3. The vertex is (−4, 2). The negative a means a reflection across the x-axis and opening downward, and the magnitude 3 gives a vertical stretch by a factor of 3 (the graph is narrower than the basic parabola). The inside term (x + 4) indicates a left shift of 4 units. So the description that matches has vertex (−4, 2); vertical stretch by factor 3; reflection across the x-axis; and opens downward.

In vertex form, y = a(x − h)^2 + k, the vertex is (h, k). The sign and size of a tell how the graph stretches, flips, and which way it opens: if a is negative, the parabola reflects across the x-axis and opens downward; if |a| > 1, the graph is vertically stretched (narrower) by a factor of |a|; if |a| < 1, it’s vertically shrunk (wider).

For y = -3(x + 4)^2 + 2, rewrite as y = a(x − h)^2 + k with h = −4, k = 2, a = −3. The vertex is (−4, 2). The negative a means a reflection across the x-axis and opening downward, and the magnitude 3 gives a vertical stretch by a factor of 3 (the graph is narrower than the basic parabola). The inside term (x + 4) indicates a left shift of 4 units.

So the description that matches has vertex (−4, 2); vertical stretch by factor 3; reflection across the x-axis; and opens downward.

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