What is the vertex of the parabola y = -3(x + 4)^2 + 2?

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Multiple Choice

What is the vertex of the parabola y = -3(x + 4)^2 + 2?

Explanation:
In vertex form, y = a(x − h)^2 + k, the vertex is (h, k). Look at y = -3(x + 4)^2 + 2 as y = -3(x − (-4))^2 + 2, so h = -4 and k = 2. Therefore the vertex is (-4, 2). The negative coefficient only affects the opening direction and width, not the vertex location; you can confirm by plugging x = -4, which makes the squared term zero and yields y = 2.

In vertex form, y = a(x − h)^2 + k, the vertex is (h, k). Look at y = -3(x + 4)^2 + 2 as y = -3(x − (-4))^2 + 2, so h = -4 and k = 2. Therefore the vertex is (-4, 2). The negative coefficient only affects the opening direction and width, not the vertex location; you can confirm by plugging x = -4, which makes the squared term zero and yields y = 2.

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